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gogolik [260]
4 years ago
15

Chosen answer is wrong, please help!

Mathematics
2 answers:
MArishka [77]4 years ago
5 0

Answer:

x ≠ 8

Step-by-step explanation:

(\frac{f}{g} )(x) = \frac{f(x)}{g(x)} = \frac{2x+5}{x-8}

The denominator of (\frac{f}{g} )(x) cannot be zero as this would make (\frac{f}{g} )(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x - 8 = 0 ⇒ x = 8 ← excluded value

Thus

domain is all values of x ∈ R , x ≠ 8

Leviafan [203]4 years ago
3 0

Answer:

A

Step-by-step explanation:

So we have the two functions:

f(x)=2x+5\text{ and } g(x)=x-8

And we want to find (f/g)(x).

This is the same as:

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}

So, substitute (2x+5) for f(x) and (x-8) for g(x). So:

=\frac{2x+5}{x-8}

Now, we want to find the domain.

Note that this is a rational function. The domain of a rational function is always all real numbers <em>except</em> when the denominator equals 0. This is because, remember, you can't divide by 0!

So, to find the domain restrictions, set the denominator equal to 0 and solve for x. So:

x-8=0

Solve for x. Add 8 to both sides:

x\neq8

So, our domain is all real numbers except for 8. We can check this, when x is 8, our function is 21/0, which is undefined.

Therefore, our answer is A.

And we're done!

Edit: Typo

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Take the amount that he pays for his mortgage, so $2042, and divide that by his total pay, $5950. You’ll get .34016907. Then to make a decimal into a percentage, you multiply it by 100. This gives you 34%, meaning he spends less than the national average on housing.
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3 years ago
Find an ordered pair to represent a in the equation<br> a=2b+c if b=(6,3) and c=(-4,8)
zaharov [31]

Answer:

The ordered pair to represent a in the equation a=2b+c if b=(6,3) and c=(-4,8) is: a=(8,14)

Step-by-step explanation:

b=(6,3)

c=(-4,8)

a=2b+c

Replacing b and c in the equation above:

a=2(6,3)+(-4,8)

Multiplying:

a=(2*6,2*3)+(-4,8)

a=(12,6)+(-4,8)

Adding:

a=(12+(-4),6+8)

a=(12-4,14)

a=(8,14)

8 0
3 years ago
Simplify 36x^2/64x^2y
aniked [119]

Answer:  3/4

Step-by-step explanation:

1. square root the denominator and nominator, 36= 6 and 64= 8

2. put them together (6/8)

3. simplify 6/8

4. 6/8 divided by 2

5. 3/4 is your answer

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3 years ago
Read 2 more answers
The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

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