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ruslelena [56]
3 years ago
11

Last month, Belinda worked 160 hours at a rate of 10.00 per hour. If her employer retains of her gross salary, is 1,500 reasonab

le estimate of her net salary
Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

100

Step-by-step explanation:

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10.36 and you will get 19.30
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At City Burger, 4 of the last 8 customers wanted cheese on their burgers. What is the experimental probability that the next cus
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1/2 chance bc 4 over 8 is 1/2
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Help plzzzSolution set of 25x2 – 1 = 0 is ____________.
kari74 [83]

Answer:

x = 1/5 ,  and   x = - 1/5

Step-by-step explanation:

25x² – 1 = 0

5²x² - 1² = 0

(5x - 1)(5x + 1) = 0

5x -1 = 0,  5x + 1 = 0

x = 1/5 ,     x = - 1/5

8 0
3 years ago
Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y
castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Fail the test.
  • Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

  • 46% of 37%(are fit).
  • 100% of 63%(not fit).

Hence:

P(A) = 0.46(0.37) + 0.63 = 0.8002

The probability of both failing the test and being unfit is:

P(A \cap B) = 0.63

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0
2 years ago
Help quick! Sheet attached 30 points on offer!
ddd [48]

Answer:

72

Step-by-step explanation:

1/2 of 96 = 48

1/2 of 48 = 24

48 + 24 = 72


8 0
2 years ago
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