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3 years ago

Last one lol I promise

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

Answer:

2 point/answer

Step-by-step explanation:

-4/5 only in 1 or 2 points

-1/2 y in 1 point

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Help me with all of 9

TEA [102]

A. 4/9
b. 3/4
c. 9/3
d. 2/9
e. 1/1
I hope that helped you. :)

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4 years ago

Read 2 more answers

Express in a single natural logarithm ln16-ln8

Sindrei [870]

Answer:

ln 2.

Step-by-step explanation:

One of the rules of logarithms is

ln a - ln b = ln a/b.

So ln 16 - ln 8 = ln 16/8

= ln 2.

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3 years ago

What is the volume of a cylinder?

pav-90 [236]

V=π r^(2)h
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3 years ago

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for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

4 years ago

Someone please help me with this

Taya2010 [7]

The answer is clearly C because it just is

5 0

4 years ago