Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Answer:
P=646
R=5%
T=2yrs
I=?
I=PRT/100
I= 646*5*2/100
I= 64.6
Step-by-step explanation:
Answer:
1. 1 1/2 feet
2. 0.46
3a. 0.62 I'm not sure if this one's correct, it's worded weird
3b. -3.43
3c. 0.14
3d. -0.481
Answer:
256
Step-by-step explanation:
Hope this helps!
If not, I am sorry.
Answer:
The sale price is 
The expression is 
Step-by-step explanation:
we know that
The sale price is equal to subtract the discount price from the original price
The discount price is equal to multiply the original price by the percent discount in decimal form
Let
x ----> the sale price
y ---> discount price
----> percent discount in decimal form
substitute
therefore
the expression is
