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NISA [10]
4 years ago
7

A certain gas expands to fill a 3 L container. Its mass is measured to be 0.6 kg. What is its density?

Chemistry
1 answer:
qwelly [4]4 years ago
7 0

Answer:

The density of gas is 0.2 Kg / L.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass = 0,6 Kg

volume= 3 L

density = ?

Now we will put the values in the formula,

d= m/v

d = 0.6 Kg / 3L

d = 0.2 Kg / L

The density of gas is 0.2 Kg / L.

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An aqueous solution of sodium sulfide is allowed to react with an aqueous solution of magnesium chloride.
olya-2409 [2.1K]

Answer : The correct option is, (b) 2Na^+

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

Na_2S(aq)+MgCl_2(aq)\rightarrow 2NaCl(aq)+MgS(s)

The complete ionic equation in separated aqueous solution will be,

2Na^+(aq)+S^{2-}(aq)+Mg^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2Na^+(aq)+2Cl^{-}(aq)+MgS(s)

In this equation the species Na^+\text{ and }Cl^{-} are the spectator ions.

Hence, the complete ionic equation contains specie is 2Na^+

4 0
3 years ago
g Using the complex based titration system: 50.00 mL 0.00250 M Ca2 titrated with 0.0050 M EDTA, buffered at pH 11.0 determine (i
kobusy [5.1K]

Answer:

Explanation:

a).

conc of Ca²⁺ =0.0025 M

pCa = -log(0.0025) = 2.6

logK,= 10.65 So lc = 4.47 x 10.

Formation constant of Ca(EDTA)]-z= 4.47 x 10¹⁰ At pH = 11, the fraction of EDTA that exists Y⁻⁴ is  \alpha_{Y^{-4}} =0.81

So the Conditional Formation constant= K_f =0.81x 4.47 x10¹⁰

=3.62x10¹⁰

b)

At Equivalence point:

Ca²⁺ forms 1:1 complex with EDTA At equivalence point,

Number of moles of Ca²⁺= Number of moles of EDTA Number of moles of Ca²⁺ = M×V = 0.00250 M × 50.00 mL = 0.125 mol

Number of moles of EDTA= 0.125 mol

Volume of EDTA required = moles/Molarity = 0.125 mol / 0.0050 M = 25.00 mL  

V e= 25.00 mL  

At equivalence point, all Ca²⁺ is converted to [CaY²⁻] complex. So the concentration of Ca²⁺ is determined by the dissociation of [CaY²⁻] complex.  

[CaY^{2-}] = \frac{Initial,moles,of, Ca^{2+}}{Total,Volume} = \frac{0.125mol}{(50.00+25.00)mL} = 0.001667M

                                                            {K^'}_f

                       Ca²⁺      +      Y⁴          ⇄     CaY²⁻

Initial                 0                  0                      0.001667

change             +x                  +x                     -x

equilibrium        x                    x                    0.001667 - x

{K^'}_f = \frac{[CaY^{2-}]}{[Ca^{2+}][Y^4]}=\frac{0.001667-x}{x.x} =\frac{0.001667-x}{x^2}\\\\x^2 = \frac{0.001667-x}{{K^'}_f}\\ \\

x^2=\frac{0.001667}{3.62\times10^{10}}=4.61\exp-14

x = 2.15×10⁻⁷

[Ca+2] = 2.15x10⁻⁷ M  

pca = —log(2 15x101= 6.7

3 0
4 years ago
EASY QUICK CHEM QUESTION!! Which line indicates a higher reaction rate?
ad-work [718]
2. B because it has a lower activation energy.

idk because you have no picture with the lines on it

3 0
4 years ago
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The sum of the protons and neutrons in an atom is its
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The atomic mass is the sum of the protons and neutrons in an atom
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A type of force where objects touch each other ​
leonid [27]

Answer:

contact force

Explanation:

I have no idea why

3 0
3 years ago
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