Answer:
The answer is D
Step-by-step explanation:
- Let's see all choices in detail
A . 0 it is correct because 0 is an integer
B .It seems like rational number but it is not simplified yet so -18 \ 2= -9
C .

D . 4\5 it is decimal so it is rational number not integer
I hope u like it
If these triangles are congruent, then side RS is congruent to side TV and that means that y = 4 - x. If y = 4-x, we can sub that into the next equation where side RV = side ST and 1 = 4x - y. If y = 4-x, we sub in accordingly to get 1 =4x - (4 - x). That simplifies to 1 = 4x - 4 + x which is, combining like terms, 5 = 5x. That means that x = 1. If x = 1, and y = 4 - x, then y = 4 - 1 and y = 3. There you go!
In(xy) = e^(x+y)
(xy)'/xy = (x+y)' e^(x+y)
(x'y + xy')/xy = (1+y') e^(x+y)
(y + xy')/xy = (1+y')e^(x+y) and simplify
Hope this helps
Decimal: 1.4 (35 divided by 25 is 1.4)
Percentage: 140% ( move decimal point two spaces to the right)
Answer:
The coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are 
Step-by-step explanation:
We need to find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)
The midpoint of line segment can be found using formula:

We have 
Putting values and finding midpoint

So, the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are 