Answer:
0.9177
Step-by-step explanation:
let us first represent the two failure modes with respect to time as follows
R₁(t) for external conditions
R₂(t) for wear out condition ( Wiebull )
Now,
where t = time in years = 1,
n = failure rate constant = 0.07
Also,
where t = time in years = 1
where Q = characteristic life in years = 10
and B = the shape parameter = 1.8
Substituting values into equation 1
Substituting values into equation 2
let the <em>system reliability </em>for a design life of one year be Rs(t)
hence,
Rs(t) = R1(t) * R2(t)
t = 1
![Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713](https://tex.z-dn.net/?f=Rs%281%29%20%3D%20%5Be%5E%7B-0.07%7D%20%5D%20%2A%20%5Be%5E%7B-0.0158%7D%20%5D%20%3D%200.917713)
Rs(1) = 0.9177 (approx to four decimal places)
You would have to use the quadratic formula because it’s not a perfect square
Step-by-step explanation:
14a. One method is two solve for x. Edit: I accidentally press sent. Repost the question and I'll answer it.
The Answer would be C, because if you divide 3/4 by 2/3 you have to switch numerators and denominator for 2/4, once you multiply that you get 9/8 you change that to a mixed number. Then you get C
Answer: option A. 30 °.
Explanation:
1) Draw this triangle: Eyes - Ship A - height of the cliff:
The angle of the vertix where the eyes are is: 90° - depreesion angle = 90° - 60° = 30°.
2) opossite leg = horizontal distance to the ship A = x
3) adjacent leg = height of the cliff = 1500 feet
4) tan(30°) = x / 1500 feet => x = 1500 tan(30°) = 1500 √3 / 3 = 500√3
5) Draw the triangle of the eyes - ship B - hieght of the cliff
6) The unknown is the depression angle of the eyes with ship B, α
7) opposite leg = 500√3 feet + 1000√3 feet = 1500√3 feet
8) adjacent leg = height of the cliff = 1500 feet
9) tan(α) = opposite leg / adjacent leg = 1500√3 / 1500 = √3
10) α = arctan(√3) = 60°
11) Depression angle = 90° - 60° = 30° Which is the answer
