Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)
v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol
n(Na₂S)=n{Cd(NO₃)₂}=cv
m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv
m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
Answer:
The metal strip on the left has a lower activity than the one on the right.
(Took the exam)
Answer:
Answer is Object 2 (which has a density of 1.9 g/cm³).
Explanation;
When object is floating, the weight of that object is less than the up thrust on it.
When an object fully submerged and floating, then the weight of that object is equal to the up thrust on it.
This is known as the Archemide's principle.
Both up thrust and weight depends on the density. Hence, if the density of the solution is high, then the up thrust also high. If the density high, the the weight of the object also high.
Hence, to sink the object in water, that object should be denser than water. Hence, answer is object 3 which has a higher density than water.
Explanation:
The chemical name begins with Hydro The Chemical name ends with hydroxide and the ide ending is changed to ic also the polyatomic ate ending changed to ic