Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.
Explanation:
The conjecture, #angleA and angleC# allows us to write the following equation:
#angleA + angleC=180^@#
Substitute the equivalent expressions in terms of x:
#x+2+ x-2 = 180^@#
#2x = 180^@#
#x = 90^@#
From this we can compute the measures of all of the angles.
#angleA=92^@#
#angleB=100^@#
#angleC=88^@#
<span>#angleD= 80^@#</span>
Exponent rules : (a^m)^n = a^(mn) and a^0 = 1
(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
The answer would be 28.
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Here's my work:
Remember PEMDAS:
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Also, remember to always go left to right.
(6+2)^2-4*3
Square everything in the parenthesis.
36+4-4*3
Multiply where you see a multiplication symbol from left to right.
36+4-12
Add.
40-12
Subtract.
28
Done!
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I hope I was able to guide and help you on this.
9514 1404 393
Answer:
1372π/3 cm^3 ≈ 1436.8 cm^3
Step-by-step explanation:
The diameter and height of the cylinder are both 14 cm. The resulting solid will be a 14 cm sphere. Its volume is ...
V = 4/3πr^3 = 4/3π(7 cm)^3 = 1372π/3 cm^3 ≈ 1436.8 cm^3
I believe the answer would be C. u subtract the 5 from both sides and divide by the -4 and flip the inequality. it has to be greater than than 13/4.
