Answer:- 10 L of ethane.
Solution:- The given balanced equation is:
From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.
Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:
= 
From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L
Hence, 10 L of ethane will be remaining.
Answer:
The value of 
is 0.02495.
Explanation:
Initial concentration of 
gas = 0.675 M
Initial concentration of 
gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M
initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
![K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BS%28CH_2CH_2Cl%29_2%5D%7D%7B%5BSCl_2%5D%5BC_2H_4%5D%5E2%7D)
The relation between and 
are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:
The value of is 0.02495.
Answer:
H2SO4 + Cu(OH)2 ---> CuSO4+ 2H2O
Answer:
hope this helped
Explanation:
Radiant energy is created through electromagnetic waves and was discovered in 1885 by Sir William Crookes. Fields in which this terminology is most often used are telecommunications, heating, radiometry, lighting, and in terms of energy created from the sun.
