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3 years ago

Why do larger gases such as Neon produce more color bands (line spectra) than smaller gases like Hydrogen?

1 answer:

7 0

Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
Hydrogen has only one orbital in which an electron orbits. At the excited state, that is, when the electron gains energy, the number of energy level it can transcend is very few. For larger elements, they have more orbitals and when excited, they can move from the ground state to other energy levels at which they produce various unique spectral lines.

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What are the energy transformations taking place in your alarm clock

kogti [31]

Answer:

Explanation:

The clock now has potential energy. When the alarm rings, the potential energy is converted into kinetic energy and sound energy.

Alarm clock runs due to the electrical energy. Due to the electric current, the electric motor rotates the blade. It means that the electrical energy is converted into mechanical energy.

The mechanical energy finally generates vibrations which cause sound.

Thus, energy transformation which takes place in alarm clock will follow the order-

Electrical to mechanical to sound.

5 0

3 years ago

When a 7.00 g7.00 g sample of KBrKBr is dissolved in water in a calorimeter that has a total heat capacity of 2.72 kJ⋅K−1,2.72 k

algol13

Answer : The molar heat of solution of KBr is 19.9 kJ/mol

Explanation :

Mass of KBr = 7.00 g

Molar mass of KBr = 119 g/mole

Heat capacity = 2.72 kJ/K

Change in temperature = 0.430 K

First we have to calculate the moles of KBr.

$\text{ Moles of }KBr=\frac{\text{ Mass of }KBr}{\text{ Molar mass of }KBr}=\frac{7.00g}{119g/mole}=0.0588moles$

Now we have to calculate the heat of the reaction.

$q=c\times \Delta T$

where,

q = amount of heat = ?

$c$ = heat capacity = $2.72kJ/K$

$\Delta T$ = change in temperature = 0.430 K

Now put all the given values in the above formula, we get:

$q=2.72kJ/K\times 0.430K$

$q=1.17kJ$

Now we have to calculate the molar heat of solution of KBr.

$\text{Molar heat of solution of }KBr=\frac{q}{n}$

where,

n = number of moles of KBr

$\text{Molar heat of solution of }KBr=\frac{1.17kJ}{0.0588moles}=19.9kJ/mol$

Therefore, the molar heat of solution of KBr is 19.9 kJ/mol

4 0

4 years ago

A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.

s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0

3 years ago

Round the mmHg readings to the nearest whole number. Round the kPa readings to the nearest tenth. Round the atm readings to the

Eva8 [605]

i love jesus and i love my mommy

6 0

2 years ago

Does sodium have a positive or negative charge after ionization?

melomori [17]

After ionization, sodium gains a net positive charge cuz sodium loses its 1 valence electron to gain the nearest stable octet which is neon{Ne}. Hope it helps

3 0

3 years ago