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son4ous [18]
3 years ago
5

Why were Opportunity and Spirit sent to Mars' surface? A. to look for alien life B. to study the rocks and soil C. to study the

atmosphere D. to mine for specific minerals
Chemistry
2 answers:
DanielleElmas [232]3 years ago
6 0
Mine for specific minerals. because we have done all the other things already
alexandr1967 [171]3 years ago
5 0
D. to mine for specific minerals

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2 years ago
If a chemist has 2.3 moles of arsenic that has a molar mass of 74.92g/mol, which would be the best way to find out how many atom
scZoUnD [109]
Mulitply 2.3 by avogadros #
4 0
3 years ago
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Which of the following factors affects the strength of the gravitational force between two objects?
mash [69]
D. the distance between the objects
6 0
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What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?
vova2212 [387]
The volume of SO2 produced at 325k   is calculated as  below

calculate  the moles of SO2 produced  which  is calculated as follows

write the  reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2

find the   moles  of  HCl  used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles

by  use of mole ratio between  HCl to  SO2  which is  2:1 the moles of SO2 is therefore = 0.411 /2 =0.206  moles  of SO2

use the idea  gas  equation  to calculate the volume SO2
that is V=nRT/P  
where  n=0.206  moles
          R(gas constant) = 0.082 L.atm/ mol.k
         T=325 K
          P=1.35 atm

V=(0.206 moles x  0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2

3 0
3 years ago
The complete combustion of a sample of propane produced 2.641 grams of carbon dioxide and 1.442 grams of water as the only produ
ohaa [14]
A general equation for a combustion reaction would be expressed as follows:

CxHy + (x+y/2)O2 = xCO2 + y/2H2O

Propane would obviously would only have carbon and hydrogen in its structure. Assuming a complete combustion, all of the carbon atoms would go to carbon dioxide and all of the hydrogen atoms to water. To determine the empirical, we determine the number of carbon and hydrogen atoms present.

moles C = 2.461 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.06 mol C

moles H = 1.442 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H ) = 0.16 mol H

Then, we divide the smallest amount to the each mole of the atoms. We do as follows:

C = 0.06 / 0.06 = 1
H = 0.16 / 0.06 = 2.67

Then we multiply a number in order to obtain a whole number ratio between the atoms.

1        CH2.67
2       C2H5.34
3       C3H8   <-------- empirical formula
8 0
3 years ago
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