Answer:
Extractive metallurgy
Explanation:
Extractive metallurgy is the practice of removing valuable metals from an ore and refining the extracted raw metals into a purer form.
The oil slick thick = 1.256 x 10⁻⁴ cm
<h3>Further explanation</h3>
Volume is a derivative quantity derived from the length of the principal
The unit of volume can be expressed in liters or milliliters or cubic meters
The conversion is
1 cc = 1 cm3
1 dm = 1 Liter
1 L = 1.06 quart
<em>so for 1 quart = 0.943 L</em>

Volume of oil dumped = volume of swimming pool

Answer:
iron sulfate
Explanation:
Electrostatic attraction as bonds between ions is characteristic of the electrovalent bond or the ionic bond
In this type of bond, there is electron transfer from one atom to another. The atom that looses electrons become positively charged while the atom that gains electrons becomes negatively charged.
In iron sulfate, there is electrostatic attraction between Fe II ions and sulphate ions, making iron sulfate an ionic compound.
Answer:
The answer to your question is 8.28 g of glucose
Explanation:
Data
Glucose (C₆H₁₂O₆) = ?
Ethanol (CH₃CH₂OH)
Carbon dioxide (CO₂) = 2.25 l
Pressure = 1 atm
T = 295°K
Reaction
C₆H₁₂O₆ ⇒ 2C₂H₅OH(l) +2CO₂(g)
- Calculate the number of moles
PV = nRT
Solve for n

Substitution

Simplification
n = 0.092
- Calculate the mass of glucose
1 mol of glucose --------------- 2 moles of carbon dioxide
x --------------- 0.092 moles
x = (0.092 x 1) / 2
x = 0.046 moles of glucose
Molecular weight of glucose = 180 g
180 g of glucose --------------- 1 mol
x g ---------------0.046 moles
x = (0.046 x 180) / 1
x = 8.28 g of glucose