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Hoochie [10]
3 years ago
15

Calculate the energy required to ionize a ground state hydrogen atom. Report your answer in kilojoules. Socratic.Org

Chemistry
1 answer:
sveticcg [70]3 years ago
7 0
<h3>Answer:</h3>

           ΔE  =  2.18 × 10⁻²¹ kJ

<h3>Solution:</h3>

Using Bohr Energy Equation,

                                    ΔE  =  - R (1/nₐ² - 1/nₓ²)

Where;

           R  =  Rydberg's constant  =  2.18 × 10⁻¹⁸ J

           nₐ  =  Infinity  =  ∞   (electron removed from H atom)

           nₓ  =  1   (Ground state of H atom)

Putting Values in equation 1,

                                    ΔE  =  - 2.18 × 10⁻¹⁸ J × ( 1/∞² - 1/1²)

                                    ΔE  =  - 2.18 × 10⁻¹⁸ J × ( 0 - 1)

                                    ΔE  =  - 2.18 × 10⁻¹⁸ J × (-1)

                                    ΔE  =  2.18 × 10⁻¹⁸ J

                                    ΔE  = 2.18 × 10⁻²¹ kJ

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What is oxidized in a galvanic cell with aluminum and gold electrodes ?
k0ka [10]

Answer:

Aluminum metal

Explanation:

In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.

First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:

Al^{3+}+3e^-\rightarrow Al; E^o=-1.66 V

Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.

Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.

Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):Al\rightarrow Al^{3+}+3e^-; E^o=1.66 V\\Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Notice that the overall cell potential upon summing is:

E_{cell}=1.66 V + 1.50 V=3.16 V

Meaning we obey the law of galvanic cells.

Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.

6 0
3 years ago
Help if possible!<br> Picture attached with the problems.
MAVERICK [17]
1. 1 M , 2 M , 1 M
2. 10 mol , 0.1 mol , 0.5 mol
3. 0.5 L , 6.6 L , 5/21 L

M = mol/L
8 0
2 years ago
How many ants would 6 giant anteaters need to eat in one year to get the matter and energy they need? Write a simple formula to
prohojiy [21]

Answer:

180,000 ants

Explanation:

For this problem we can create the following simple formula to solve this problem...

f(x) = 6x

where the variable x represents the number of ants that a single Anteater needs to eat per day. After a quick online search we can see that a single Anteater eats roughly 30,000 ants per day. If we use this value and plug it into the simple formula we can get the total number of ants 6 anteaters need to eat to survive.

f(x) = 6 * 30,000

f(x) = 180,000

7 0
2 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
Which solution when mixed with a drop of bromthymol blue will cause the indicator to change from blue to yellow?
Mashutka [201]
When you mix 0.1 M HCI, with a drop of brothymol blje, this will make the incubator to change from blue to yellow.
3 0
3 years ago
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