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3 years ago

Which kind of heat transfer does this represent

Mathematics

2 answers:

Kaylis [27]3 years ago

6 0

I believe it is a chemical transfer

NikAS [45]3 years ago

6 0

Chemical transfer I think. I'm pretty sure

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The data in which table represents a linear function that has a slope of zero?

kherson [118]

Answer:the last table

Step-by-step explanation:

If all the x’s are the same, there is zero slope, if all the y’s are the same like the first table, the slope is undefined, not zero

8 0

3 years ago

Read 2 more answers

paulette has arrived at cape horn. there are five penguins waiting to cross over to antarctica. jim goes before john but after j

Nikolay [14]

Well, this is a guess. Jim goes before john, but after joe. So Jim is second. John is third, so that leaved Joe.

Joe, Jim, John. But I don't know about the other 2.

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sorry if this doesn't help

6 0

3 years ago

QUICK HOW DO YOU SIMPLIFY THIS EQUATION

Yanka [14]

20.25-9(1/2)+11
=20.25-4.5+11
=26.75

3 0

3 years ago

Given interest of $10,510 at 12 percent for 30 days one can calculate the principal as:

gtnhenbr [62]

Answer:

$1,065,597.22

Step-by-step explanation:

Simple interest = Principal * Rate * Time/100

10,510 = P * 12 * 30/365*100

10,510*365*100 = 360P

383,615,000 = 360P

Note that the time was converted to years by dividing by 365

P = 383,615,000/360

P = $1,065,597.22

Hence the principal is $1,065,597.22

7 0

2 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago