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Gelneren [198K]

3 years ago

6

What is the height of a cylinder with a volume of cubic meters and a radius of 6 meters?

2 answers:

Doss [256]3 years ago

8 0

Ok, so i got 144 cubic cubic meters by multiplying 6 by 6 by 4. Tell me if it's correct because i'm not the best at Math, but I checked and rechecked it. <span />

Ray Of Light [21]3 years ago

6 0

I think volume is not given by mistake..!!?

let's take volume =1 cubic meter
then

Volume of cylinder = pie * r^2 * h

and V =1, r = 6, pie= 3.14

so, h= 1 /(pie* 36)

h= 0.88 cm

Note: i assumed volume =1

hope it helped

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Estimate the indicated probability by using the normal approximation as an approximation to the binomial distribution. (PROBLEMS

S_A_V [24]

Answer:

4

$P(X \ge 219 ) = 0.093$

5

$P(X \ge 219 ) = 0.1038$

Step-by-step explanation:

From the question we are told that

The percentage of hair dryers that are defective is p=2% $= 0.02$

The sample size is $n =10000$

The random number is x = 219

The mean of this data set is evaluated as

$\mu = n* p$

substituting values

$\mu = 10000 * 0.02$

$\mu =200$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[200 (1 -0.02)]}$

$\sigma = 14$

Since it is a one tail test the degree of freedom is

df = 0.5

So

$x_l = x- 0.5$

$x = 219 - 0.5$

$x = 218.05$

Now applying normal approximation

$P(X \ge 219 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{218.5 - 200}{14} )$

$P(X \ge 219 ) = P(z > 1.32} )$

From the z-table

$P(X \ge 219 ) = 0.093$

Considering Question 5

The random number is x = 90

The mean is $\mu = n * p$

Where n = 100

and p = 0.85

So

$\mu = 0.85 *100$

$\mu = 85$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[85 (1 -0.85)]}$

$\sigma = 3.5707$

Since it is a one tail test the degree of freedom is

df = 0.5

Now applying normal approximation

$P(X \ge 90 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{89.5 - 85}{3.5707} )$

$P(X \ge 219 ) = P(z > 1.2603} )$

From the z-table

$P(X \ge 219 ) = 0.1038$

8 0

4 years ago