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zhannawk [14.2K]
3 years ago
10

Which substances ionize when they dissolve?

Chemistry
1 answer:
noname [10]3 years ago
6 0
<h3>Answer:</h3>

Ionic compounds

<h3>Explanation:</h3>

What are ionic compounds?

  • Ionic compounds are compounds that are formed due to ionic bonds between atoms.
  • Ionic bonds are formed between metallic atoms and non-metallic atoms.

What are examples of ionic compounds?

  • Examples of ionic compounds include, KCl, NaBr, MgCl₂, etc

How do ionic compound ionize in water?

  • Ionic compounds ionizes when dissolved in water to form mobile ions.
  • When dissolved in water they may serve as electrolytes due to the presence of free ions which will be responsible for conduction of electricity.
  • For example, NaCl ionizes to form Na⁺(aq) and Cl⁻(aq).
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The structural level of a protein least affected by a disruption in hydrogen bonding is the
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I think the correct answer from the choices listed above is option A. The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level. The other levels are very much affected by hydrogen bonding. Hope this answers the question.
7 0
4 years ago
How many moles are there in 24.00 g of NaCl
Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

6 0
3 years ago
4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a
yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

6 0
3 years ago
Balance sulfur and oxygen​
abruzzese [7]

Answer:

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S+O2=SO2

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