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vaieri [72.5K]
3 years ago
5

The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol

ution?
Chemistry
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

0.805 M.

Explanation:

Hello!

In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl

Next, since the volume is 0.2500 in liters, the molarity turns out:

M=\frac{0.201mol}{0.2500L} \\\\M=0.805M

Best regards!

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In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe
ad-work [718]

We know the law of conservation of mass

  • It states that mass is neither formed nor destroyed in any chemical reaction.
  • Mass of reactants=Mass of products.

Here

  • Mg and I_2 are reactants
  • MgI_2 is product with some yield.
  • Mass of reactants=10+60.0=70.0g
  • Mass of MgI_2=53.88g
  • Mass of yield=Product-MgI_2=70-53.88=16.12g

Lets find the percentage

\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100

\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100

\\ \tt\hookrightarrow 0.23028(010)=23.028\%

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2 years ago
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A base has a molarity of 1.5M w.R.T the hydroxyl ion concentration. If 7.35 cm3 of this base is taken and diluted to 147 cm3, th
daser333 [38]

Answer:

0.077M is the concentration of the hydroxyl ion

Explanation:

Dilution factor is the ratio between the aliquot that is taken of a solution and the total volume of the diluted solution.

For the problem, dilution factor is:

7.53cm³ / 147cm³ =<em> 0.05122</em>

To obtain molarity of a diluted solution you must multiply dilution factor and initial molarity of the solution, thus:

1.5 M × 0.05122 = <em>0.077M is the concentration of the hydroxyl ion</em>

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3 years ago
3. Write DISSOCIATION or IONIZATION equations for the following chemicals:
Romashka [77]

Answer:

a) HNO3 -> H+ + NO3- disassociation of Nitric Acid; to yield a Nitrate ion and a Proton, H+, or as a Hydronium ion H3O+

b) H2S04 -> Disassociation of Sulfuric Acid; simple way- 2H+ + SO4- -

c) H2S hydrogen sulphide in water is an acid; thus H+ HS- disassociation.

d) NaOH -> dissociation of Na+ + OH-; this is complete; sodium hydroxide is deliquescent, meaning it will draw water - EVEN from the air! Strong Base

e) Na2CO3 -> 2Na+ CO3- - Ionization of sodium carbonate - a salt

f) Na2S04 -> 2Na+ + SO4 - - ionization of sodium sulphate - a salt

g) NaCl​ -> Na+ + Cl- ionization of the salt, Sodium Chloride

Explanation:

Salts ionize at different rates; acids or bases dissociate; these are mostly strong acids and NaOH, a strong base.

8 0
3 years ago
Which of the following can explain the daily change in sea level observed along a coast?
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The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide. 
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Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5
Pie

acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.

so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

7 0
3 years ago
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