Answer:

Explanation:
In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case
) and the anion is the atom at the right of the name (in this case
). With this in mind, the <u>formula would be</u>
.
Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u>
. So, we have as reagents:

The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:

With this in mind, the reaction would be:

I hope it helps!
Why do so many storms target the state? The easterly winds typically blowing across Jacksonville in the summer flow out of the Azores/Bermuda high-pressure system which also steers many hurricanes into the Gulf. In June and October, storms are more likely to move up the Gulf from the south and southwest.
Answer: The frequency of this light is 
Explanation:
To calculate the wavelength of light, we use the equation:

where,
= wavelength of the light =
c = speed of light = 
= frequency of light = ?

The frequency of this light is 
Answer:
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