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finlep [7]
3 years ago
7

Nonrenewable energy resources include what types of energy ?

Chemistry
2 answers:
Alchen [17]3 years ago
6 0
All the fossil fuels...coal, oil, gas...are examples of no return enable energy resources.
sashaice [31]3 years ago
5 0
Some of the types of energy that are included in nonrenewable energy are, fossil fuels and nuclear power of some sort. hope this is what you were looking for. 
You might be interested in
What is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen​
levacccp [35]

Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

5 0
3 years ago
Someone help me i don’t understand it
Troyanec [42]
Use PV=nRT to help you
3 0
3 years ago
How to balance barium and oxygen yield barium oxide
olga55 [171]
Barium : Ba^{+2} with +2 being the charge
Oxygen : O^{-2} with -2 being the charge

The given equation can be written as:
Ba + O = BaO

Since the sum charges of Barium and Oxygen equals 0, there is no need to add subscripts.

Both Ba and O appear on the left and right side of the equation once, so there is no need to add a coefficient.

Ba + O = BaO is balanced
4 0
3 years ago
Vitamin C, also known as ascorbic acid, is composed of 40.9 percent carbon, 4.6 percent hydrogen, and 54.5 percent oxygen. The m
Vladimir79 [104]

Answer:

Molecular formula is : C₆H₈O₆  

Explanation:

40.9 % of C, 4.6 % of H, 54.5 % of O means that in 100 g of ascorbic acid, we have 40.9 g of C, 4.6 g of H and 54.5 g of O.

If 1 mol of ascorbic acid weighs 176 g, let's determine the rules of three to know the grams of each element:

100 g of compound has ___ 40.9 g C __ 4.6 g H ___ 54.5 g O

176 g compound mus have:

(176 . 40.9) / 100 = 72 g of C

(176 . 4.6) / 100 = 8 g of H

(176 . 54.5) / 100 = 96 g of O

If we convert the mass to moles:

72 g . 1 mol / 12 g = 6 C

8 g . 1 mol/ 1g = 8 H

96 g . 1mol / 16 g = 6 O

Molecular formula is : C₆H₈O₆  

In conclussion, 1 mol of ascorbic acid has 6 moles of C, 8 moles of H and 6 moles of O

6 0
3 years ago
The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustion of
aev [14]

Answer: <em>C₃H₆O</em>


Explanation:


1)  First, calculate the chemical composition, which you do using balance mass using the data given.


2) Data:


i) mass of ethyl butyrate: 2.22 mg

ii) mass of CO₂: 5.06 mg

iii) mass of H₂O: 2.06 mg


3) Solution


i) All the carbon in CO₂ produced was present in the ehtyl butyrate sample.


ii) The molar mass of CO₂ is 44.01 g/mol


iii) Use proportionality:


12.01 g C / 44.01 g CO₂ = x / 5.06 mg C  ⇒ x = 1.38 mg  C


iv) All the H in H₂O was present in the original sample of ethyl butyrate


v) The molar mass of H₂O is 18.015 g/mol


vi) Use proportionality


2.016 g H / 18.015 g H₂O = x / 2.06 mg H ⇒ x = 0.23 mg H


vii) Mass balance:


mass of O in the sample = mass of the sample - mass of H - mass of C


mass of O = 2.22 mg - 1.38 mg - 0.23 mg = 0.61 mg O.


viii) Composition:

C = 1.38 mg

H = 0.23 mg

O = 0.61 mg


Which in terms of composition is the same that:

C = 1.38 g

H = 0.23 g

O = 0.61 g


ix) Divide each by the molar atomic mass of the corresponding element, to obtain the number of moles:


C = 1.38 g / 12.01 g/mol = 0.115 mol

H = 0.23 g / 1.008 g/mol = 0.228 mol

O = 0.61 g / 16 g/mol = 0.0381 mol


x) Divide each by the least number of moles to obtain mole proportion


C = 0.115 / 0.0381 = 3.02 ≈ 3

H = 0.228 / 0.0381 = 1.98 ≈ 5.98 ≈ 6

O = 0.0381 / 0.0381 = 1


xi) Therefore the empirical formula searched is <em>C₃H₆O</em>.


7 0
3 years ago
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