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vlabodo [156]
3 years ago
15

A sample of calcium oxide has mass of 2.80 g. The molar mass of CaO is 58.08 g/mold how many moles of CaO does this sample conta

in
Chemistry
1 answer:
finlep [7]3 years ago
3 0
Hi!

To convert grams to moles, you need to divide the amount (grams) of your substance by its molar mass, both of which are given to you.

28 g CaO / 58.08 g/mol CaO = 0.4820936639 moles of CaO
(And 28 contains two significant digits, so you will round this to 0.48 moles.)

Good luck!
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What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
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when t=19.8 hrs,
x= x_{0}  e^{19.8 k}, 
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ln \frac{1}{8} =19.8 k,

ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
-3 ln2=19.8k
k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,
 \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } 
\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,
2= e^{ \frac{ln2}{6.6}t } ,
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8 0
4 years ago
The half-life for the second-order decomposition of HI is 15.4 s when the initial concentration of HI is 0.67 M. What is the rat
larisa [96]

Answer:

The correct answer is option C.

Explanation:

Half life for second order kinetics is given by:

t_{\frac{1}{2}=\frac{1}{k\times A_0}

t_{\frac{1}{2} = half life = 15.4 s

k = rate constant =?

A_0 = initial concentration = 0.67 M

15.4 s=\frac{1}{k\times 0.67 M}

k=\frac{1}{15.4 s\times 0.67 M}=0.09692 M^{-1} s^{-1}=9.69\times 10^{-2}M^{-1} s^{-1}\approx 9.7\times 10^{-2} M^{-1} s^{-1}

9.7\times 10^{-2} M^{-1} s^{-1}  is the rate constant for this reaction.

4 0
3 years ago
A _____ equation is a chemical equation that does not indicate relative amounts of reactants and products. A. balanced B. activi
Alla [95]
A Skeleton equation is a chemical equation that does not indicate relative amounts of reactants and products. Answer: D)
8 0
3 years ago
How does the design of an experiment relate to the method of difference?
BartSMP [9]

Answer:

The design of experiments (DOE, DOX, or experimental design) is the design of any task that aims to describe and explain the variation of information under conditions that are hypothesized to reflect the variation. The term is generally associated with experiments in which the design introduces conditions that directly affect the variation, but may also refer to the design of quasi-experiments, in which natural conditions that influence the variation are selected for observation.

Explanation:

5 0
3 years ago
An atom of a particular element is traveling at 1.00% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-
ExtremeBDS [4]

Answer:

The given atom is of Ca.

Explanation:

Given data:

Speed of atom = 1% of speed of light

De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)

What is element = ?

Solution:

Formula:

m = h/λv

m = mass of particle

h  = planks constant

v = speed of particle

λ = wavelength

Now we will put the values in formula.

m = h/λv

m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s

m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s

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or

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Now here we will use the Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Now in given problem,

6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg

40.3×10⁻³×10³g/mol

40.3  g/mol

So the given atom is of Ca.

8 0
3 years ago
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