Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH.
We are given:
Putting values in above equation, we get:
Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Answer:
Cesium has one valence electron that can be removed from itself resulting to its stable monatomic ion of Cs+ .
Explanation:
<span>the electron configuration of the neutral Atom
1s2 2s1
should be your answer have a good day </span>
Answer:
311.25k
Explanation:
The question assumes heat is not lost to the surroundings, therefore
heat emitted from hotter sample ( 
)= heat absorbed by the less hotter sample( 
)
The relationship between heat (q), mass (m) and temperature (t) is 
where c is specific heat capacity, 
temperature change.
= 
equating both heat emitted and absorb
where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.
C will cancel out since both are water and they have the same specific heat capacity.
so we have
where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?
-50 * (
- 330) = 30 * ( - 280)
-50 + 16500 = 30 - 8400
80 = 16500+8400
80 = 24900
= 24900/80 = 311.25k
