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olasank [31]
3 years ago
15

If it takes Ashley 10 seconds to run from the batter's box to first base at an average speed

Physics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

65 meters

Explanation:

Time = 10 seconds

Speed = 6.5 m/s

Distance = ?

Distance = speed\times time\\\\d = 6.5 \times 10 \\d = 65 m

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Alai is comparing the physical property of two materials. He is hitting each with a hammer to observe what happens. What physica
dalvyx [7]

Answer:

C:Hardness

Explanation:

if youre hitting something your going to see wich one breaks first

8 0
2 years ago
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How should ready-to-eat food be stored after it has cooled?
snow_lady [41]

Answer:

The answer is most likely C.

Ready-to-eat foods are stored at the top of the fridge, away from raw foods so that harmful bacteria cannot transfer from the raw food to the cooked food. Raw meat, poultry and fish in sealed containers to stop them touching or dripping onto other foods.

5 0
2 years ago
A car is cruising at a steady speed of 35 mph. Suddenly, a cuddly puppy runs out into the road. The driver takes 1.7 seconds to
Schach [20]

Answer:

The distance traveled is 0.037 mi

Explanation:

The equation for the position and velocity of an accelerated object is:

x = x0 + v0 * t + 1/2 * a * t²

v = v0 + a * t

where

x = position at time t

x0 = initial position

t = time

a = acceleration

v0 = initial velocity

If the velocity is constant, then a = 0 and the position will be:

x = x0 + v * t where "v" is the velocity

First, let´s find the distance traveled until the driver push the brake:

The speed is constant. Then:

x = x0 + v * t (considering the origin of the reference system to be located at the point at which the driver sees the puppy, x0 = 0)

x = 35 mi/h (1 h / 3600 s) * 1.7 s = 0.017 mi

Then, the drivers moves with constant acceleration until the car stops (v = 0)

From the equation for velocity:

v = v0 + a * t

Since v = 0, we can obtain the acceleration of the car until it stops. With that acceleration, we can calculate how much distance the car moves before it stops.

0 = v0 + a * t

-v0 / t = a

-35 mi/h (1 h / 3600s) / 4.0 s = a

a = -2.4 x 10⁻³ mi/s²

The distance traveled will be:

x = x0 + v0 * t + 1/2 * a * t²

Now x0 will be the distance traveled before the driver slows down.

x = 0.017 mi + 35 mi/h (1 h / 3600s) * 4 s + 1/2 * ( -2.4 x 10⁻³ mi/s²) * (4s)²

x = 0.037 mi

6 0
3 years ago
You have a meteorite sample and you decide to use the uranium-235/lead-207 system to date it. After analysis, you find that it h
storchak [24]

Originally there must been

1,4775E6 + 2.25E4 = 147.75E4 + 2.25E4 = 150E4 present at start

% = 2.25 / 150 = 1.5 %      of 235 U left

5 0
2 years ago
"What is the overall length limitation of a UTP cable run from the telecommunications closet to a networking device in the work
Goryan [66]

Answer:

90-100meters

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The overall length limitation of a UTP cable is 90-100meters. Once this limitation is reached, a repeater is employed to transfer data.

4 0
3 years ago
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