About 2 to 5 centimeters per year (1 to 2 inches per year), about the same speed that your fingernails grow. We know, then, that the outermost part of Earth consists of a series of large slabs (tectonic plates; lithospheric plates) that move slowly over the globe, powered by flow in the interior mantle
Answer:
Many objects are designed specifically to store elastic potential energy, for example: The coil spring of a wind-up clock. An archer's stretched bow. A bent diving board, just before a divers jump
Explanation:
Answer:
The maximum speed of the car should be 13.7 m/s
Explanation:
For the car to travel at a maximum safe speed , the frictional force acting should be maximum and at the same time should provide the necessary centripetal force.
Let 'k' (=0.3502) be the coefficient of friction and 'N' be the normal force acting on the surface.
Then ,
N = mg , where 'm' is the mass of the body and 'g'(=9.8) is the acceleration due to gravity.
∴ Maximum frictional force , f = kN = kmg
Centripetal force that should act on the car to move with maximum possible speed is -
, where 'v' is the velocity of the car and 'r'(=55m) is the radius of circular path.
Equating the 2 forces , we get -
∴ 
Substituting all the values , we get -
v = 13.7 m/s.
Answer:
1.2 s
Explanation:
We'll begin by calculating the length (i.e distance) of the ramp. This can be obtained by using pythagoras theory as illustrated below:
NOTE: Length of the ramp is the Hypothenus i.e the longest side.
Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:
s² = 4² + 3²
s² = 16 + 9
s² = 25
Take the square root of both side
s = √25
s = 5 m
Thus the length of the ramp is 5 m
Next, we shall determine the final velocity of the ball. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
v² = u² + 2as
v² = 3² + (2 × 2 × 5)
v² = 9 + 20
v² = 29
Take the square root of both side
v = √29
v = 5.39 m/s
Finally, we shall determine the time taken for the ball to reach the final position. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Final velocity (v) = 5.39 m/s
Time (t) =?
v = u + at
5.39 = 3 + 2t
Collect like terms
5.39 – 3 = 2t
2.39 = 2t
Divide both side by 2
t = 2.39 / 2
t = 1.2 s
Thus, it will take 1.2 s for the ball to get to the final position.
The answer would be 70. I got my answer from www.iun.edu
