<span>Using
a 12-hour clock (where the hour hand moves between the integers 1 thru
12 and the minute hand moves between the integers 0 and 59), read the
current clock time from the user and then read a time increment to add
to or subtract from the current time.</span>
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
Step-by-step explanation:
It is given that,
V = bdt i.e. V is equal to the product of b, d and t
We need to find the formula for d.
Dividing both sides of the given expression by bt
So,
Hence, is the value of d.
Answer:
-1 & -2
Step-by-step explanation:
x²+3x+2
x²+2x+x+2
(x²+2x)+(x+2)
x(x+2)+1(x+2)
(x+1)(x+2)
Answer:
A
Step-by-step explanation:
(y + 7) - (-8y + 14) = y + 7 + 8y - 14 = 9y - 7
