Let g and b represent the numbers of grandstand and bleacher tickets sold.
.. g + b = 5716 . . . . . . . . . total number of tickets sold
.. 65g +40b = 341690 . . value of tickets sold
Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25
1194 bleacher tickets were sold.
Answer:
2 2/5
Step-by-step explanation:
divide 12 into 5 you get 2.4
2.4 is the same as 2 4/10 which can be equal to 2 2/5
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
Answer :
If 18+12 is 30 and only 18 of them has pets then 70 percent have pets
