Problem 33
For each number, generate a factor tree. This is where you break a number down into smaller factors in a visual "tree" like style. The idea is to factor down to the prime factors and then you circle the common primes between each number. The values you circle are then multiplied if you circle more than one value in each tree.
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Problem 34
Xiao factored correctly but didn't pull out the GCF. So he didn't factor fully. In the case of 60 and 90, the GCF is 30. This is the largest shared factor between the two values. So we can pull out 30 to get
60+90 = 30*2+30*3 = 30*(2+3)
I'm basically using the distributive property in reverse. You can distribute the 30 back in and get 60+90 again. Notice how the inner stuff 2 and 3 have no factors in common other than 1.
Answer:
H0 : μEng = μBio
H1: μEng ≠ μBio
Step-by-step explanation:
μEng = Engineering average gpa
μBio = Biology average gpa
To test for difference between two sample means , in this case grade point average of biology majors and Engineering major.
Null hypothesis is the initial truth, which is that ; there is no difference in the mean grade point average of both biology and engineering majors
H0 : μEng = μBio
The Alternative hypothesis is the opposite of the null, which is stated has ; there is difference between the average GPA of both Engineering and Biology majors
H1: μEng ≠ μBio
Answer:
-4
Step-by-step explanation:
The slope of a line given two points is given by
m = (y2-y1)/(x2-x1)
= (-4-8)/(2 - -1)
= (-4-8)/(2+1)
= -12/3
= -4
Answer:
242
Step-by-step explanation:
7(6*6)-10
7(36)-10
252-10
=242
