The morality, molality, and mole fraction of NaOH is mathematically given as
- morality= 4 ppm
- molality=0.7936m
- x1 = 0.152
What are the morality, molality, and mole fraction of NaOH?
Question Parameters:
A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water.
Generally, the equation for the Molality is mathematically given as
molality = (mass / molar mass) x (1/ weight of solvent kg)
Therefore
M= (800 /40) x (1 /25.2)
M=0.7936m
Therefore
m= 10 x 18 / 1000
m= 0.18
Hence
x1 = 0.18 - 0.18 x1
1.18 x1 = 0.18
x1 = 0.152
Where the mole fraction is x1 = 0.152 The mass is
m= (800 / 800 + 2000) x 1000
m= 28.57 %
Hence the morality
molality = mg /L
molality= 8000 x 10^-3 / 2 L
morality= 4 ppm
In conclusion, the morality, molality, and mole fraction of NaOH are given respectively as
morality= 4 ppm
molality=0.7936m
x1 = 0.152
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