1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Illusion [34]
3 years ago
8

What does the oxidizing agent do in a redox reaction apex?

Chemistry
2 answers:
densk [106]3 years ago
6 0
Same as balancing a regular chemical reaction! Please see the related question to the bottom of this answer for how to balance a normal chemical reaction. This is for oxidation-reduction, or redox reactions ONLY! These instructions are for how to balance a reduction-oxidation, or redox reaction in aqueous solution, for both acidic and basic solution. Just follow these steps! I will illustrate each step with an example. The example will be the dissolution of copper(II) sulfide in aqueous nitric acid, shown in the following unbalanced reaction: CuS (s) + NO 3 - (aq) ---> Cu 2+ (aq) + SO 4 2- (aq) + NO (g) Step 1: Write two unbalanced half-reactions, one for the species that is being oxidized and its product, and one for the species that is reduced and its product. Here is the unbalanced half-reaction involving CuS: CuS (s) ---> Cu 2+ (aq) + SO 4 2- (aq) And the unbalanced half-reaction for NO 3 - is: NO 3 - (aq) --> NO (g) Step 2: Insert coefficients to make the numbers of atoms of all elements except oxygen and hydrogen equal on the two sides of each half-reaction. In this case, copper, sulfur, and nitrogen are already balanced in the two half-reaction, so this step is already done here. Step 3: Balance oxygen by adding H 2 O to one side of each half-reaction. CuS + 4 H 2 O ---> Cu 2+ + SO 4 2- NO 3 - --> NO + 2 H 2 O Step 4: Balance hydrogen atoms. This is done differently for acidic versus basic solutions. . For acidic solutions: Add H 3 O + to each side of each half-reaction that is "deficient" in hydrogen (the side that has fewer H's) and add an equal amount of H 2 O to the other side. For basic solutions: add H 2 O to the side of the half-reaction that is "deficient" in hydrogen and add an equal amount of OH - to the other side. Note that this step does not disrupt the oxygen balance from Step 3. In the example here, it is in acidic solution, and so we have: CuS + 12 H 2 O ---> Cu 2+ + SO 4 2- + 8 H 3 O + . NO 3 - + 4 H 3 O + --> NO + 6 H 2 O Step 5: Balance charge by inserting e - (electrons) as a reactant or product in each half-reaction. Oxidation: CuS + 12 H 2 O ---> Cu 2+ + SO 4 2- + 8 H 3 O + + 8 e - . Reduction: NO 3 - + 4 H 3 O + + 3 e - --> NO + 6 H 2 O . Step 6: Multiply the two half-reactions by numbers chosen to make the number of electrons given off by the oxidation step equal to the number taken up by the reduction step. Then add the two half-reactions. If done correctly, the electrons should cancel out (equal numbers on the reactant and product sides of the overall reaction). If H 3 O + , H 2 O, or OH - appears on both sides of the final equation, cancel out the duplication also. Here the oxidation half-reaction must be multiplied by 3 (so that 24 electrons are produced) and the reduction half-reaction must by multiplied by 8 (so that the same 24 electrons are consumed). 3 CuS + 36 H 2 O ---> 3 Cu 2+ + 3 SO 4 2- + 24 H 3 O + + 24 e - 8 NO 3 - + 32 H 3 O + + 24 e - ---> 8 NO + 48 H 2 O Adding these two together gives the following equation: 3 CuS + 36 H 2 O + 8 NO 3 - + 8 H 3 O + ---> 3 Cu 2+ + 3 SO 4 2- + 8 NO + 48 H 2 O Step 7: Finally balancing both sides for excess of H 2 O (On each side -36) This gives you the following overall balanced equation at last: 3 CuS (s) + 8 NO 3 - (aq) + 8 H 3 O + (aq) ---> 3 Cu 2+ (aq) + 3 SO 4 2- (aq) + 8 NO (g) + 12 H 2 O (l)


Anni [7]3 years ago
4 0

<u>Answer:</u> It helps in the oxidation of other substance and itself gets reduced.

<u>Explanation:</u>

Oxidizing agent is defined as the agent which helps in the oxidation of other substance and itself gets reduced. It undergoes reduction reaction in any redox reaction.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Reducing agent is defined as the agent which helps in the reduction of other substance and itself gets oxidized. It undergoes oxidation reaction in any redox reaction.

Oxidation reaction is defined as the reaction in which a substance looses electrons. The oxidation state of the substance is increased.

<u>For Example:</u> Reaction of silver nitrate with copper metal, the equation follows:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The half reactions for the above reaction are:

Oxidation half reaction:  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

Reduction half reaction:  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the above reactions, silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.

Copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.

Hence, it helps in the oxidation of other substance and itself gets reduced.

You might be interested in
Can swords shatter from cold temperatures
sp2606 [1]
Depends on how the sword is made, what materials are used and temperature used but yes they can shatter.

When molecules cool down they stop vibrating and moving as much and so they "shrink" and the metal of the sword becomes brittle. sometimes they shrink at different phases which cause tension in the sword if this tension is strong enough it can cause the metallic bonds to break causing the sword to shatter.

hope that helps 
6 0
3 years ago
The hydrogens and oxygen of a water molecule are held together by ______ bonds.
umka2103 [35]
The hydrogens and oxygen of a water molecule are held together by covalent bond
6 0
3 years ago
Read 2 more answers
What is the formula for tin(IV) sulfide?<br> A. Sn4S<br> B. SnS2<br> C. Sns<br> D. SnS4
defon

Answer:

SnS_{2}

Explanation:

The formula for tin(IV) sulfide is SnS_{2}

6 0
3 years ago
True Or False, Humanists felt strongly against comparing people to animals.
Vadim26 [7]
False beacause that was one of the first things they thought
4 0
3 years ago
Read 2 more answers
PLLLLLLLZ HELP IS NEEDED ASAP I WOULD REALLY APPRECIATE IT
Lesechka [4]

Answer:

1)Reactants

2)Light

3)An item that can increase reaction rates

4)Reactants must collide with each other

Less molecules lower the chance for collisions

The more collisions there are the higher the reaction rate

5 0
3 years ago
Other questions:
  • An 100g box have a temperature of 22 C. What temperature must a 200g box be kept at in order for both to have the same amount of
    6·1 answer
  • An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0100 M O2. At this temperature, Kc
    11·2 answers
  • Sarah added sugar to her iced tea but it is not dissolveing very quickly which can Sarah do to make the sugar dissolve faster ?
    15·1 answer
  • Which one of these is not an example of intercellular communication?
    12·1 answer
  • 22.5 mL of an HNO3 solution were titrated with 31.27 mL of a .167 M NaOH solution to reach the equivalence point. What is the mo
    10·1 answer
  • What is the reason why bubbling occurs when vinegar is mixed with baking soda?
    13·1 answer
  • Which is an example of a base?a(lemon juice b(baking soda c(an insolator d( water
    9·1 answer
  • Researchers have developed cars which navigate and steer themselves. Aside from cost, what is most likely the main factor keepin
    13·2 answers
  • How would an apple, potato, and onion all taste the same?
    9·1 answer
  • Fields of Study Alferd Wegener
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!