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antoniya [11.8K]
2 years ago
6

How many atoms are there in a molecule?

Chemistry
1 answer:
Elden [556K]2 years ago
3 0

Answer:

Do your legs hurt from running ‍♂️ through my mind all night?

Explanation:

Did you just come out of the oven? Because you're hot

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If I need 2.2 moles of CO2 , and I have excess Fe2O3 , how many moles of C do I need?
olchik [2.2K]

Answer:

0.733 mol.

Explanation:

  • From the balanced equation:

<em>2Fe₂O₃ + C → Fe + 3CO₂,</em>

It is clear that 1.0 moles of Fe₂O₃  react with 1.0 mole of C to produce 1.0 mole of Fe and 3.0 moles of CO₂.

  • Since Fe₂O₃ is in excess, C will be the limiting reactant.

<u><em>Using cross multiplication:</em></u>

1.0 mole of C produces → 3.0 moles of CO₂, from the stichiometry.

??? mole of C produces → 2.2 moles of CO₂.

∴ The no. of moles of C needed to produce 2.2 moles of CO₂ = (1.0 mole of C) (2.2 mole of CO₂) / (3.0 mole of CO₂) = 0.733 mol.

6 0
3 years ago
Mario wants to split a beam of white light into different colors. Which tool will work best?
cestrela7 [59]
The correct answer --> A
7 0
3 years ago
what volume of co2 is produced at stp when 270g of glucose are consumed in the following reaction? c6h12o6 + 6o2(g) -&gt; 6co2 (
lana [24]

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

4 0
3 years ago
Which is a possible result of rising ocean temperatures caused by global warming?
goldfiish [28.3K]
Pretty sure it’s 2, increase in strength of hurricanes
3 0
3 years ago
What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?
lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P)   \frac{3.8}{31} =0.123

Hydrogen (H)   \frac{0.371}{1} =0.371

Then you divide by the lowest number:

\frac{0.123}{0.123} = 1 for phosphorus

\frac{0.371}{0.123} = 3 for hydrogen

So the empirical formula will be:    

PH_{3}

6 0
3 years ago
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