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2 years ago

7

Based on the equation below , how many moles of carbon monoxide (CO) are needed to react completely with 1.75 moles of iron (lll

) oxide (Fe2O3)
Fe2O3(s) + 3CO(g) --->2Fe(s) + 3CO2(g)

1 answer:

blagie [28]2 years ago

3 0

From the equation:
1 mole Fe₂O₃ needs 3 moles of CO
1.75 moles require:
1.75 x 3
= 5.25 moles of CO

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The compound ncl3 is nitrogen trichloride, but alcl3 is simply aluminum chloride. why

AveGali [126]

The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride<span>.
</span><span>The compound AlCl3 is an ionic compound (metal and nonmetal), and therefore does not require prefixes. so AlCl3 is aluminum chloride.
</span><span>
Both of nitrogen and chlorine is nonmetal, but aluminum is metal. Metal with nonmetal will make an ionic compound that doesn't need prefixes.</span>

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3 years ago

Read 2 more answers

20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as

shepuryov [24]

The reaction forms 98.76 g AlCl_3.

We have the masses of two reactants, so this is a <em>limiting reactant problem</em>.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

<em>Step 1. Gather all the information</em> in one place with molar masses above the formulas and everything else below them.

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the <em>limiting reactant</em>

Calculate the moles of AlCl_3 we can obtain from each reactant.

<em>From Al</em>: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

<em>From Cl_2</em>: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

<em>Cl_2 is the limiting reactant</em> because it gives the smaller amount of AlCl_3.

<em>Step 4</em>. Calculate the <em>mass of AlCl_3</em>.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0

2 years ago

A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem

ira [324]

This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

$Q=mC(T_f-T_i)\\$

Which has to be solved for the final temperature, $T_f$ as follows:

$T_f=T_i+\frac{Q}{mC}$

Finally, we plug in the numbers to obtain:

$T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C$

However, this result is not given in the choices.

Learn more:

brainly.com/question/14383794

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2 years ago

A chemist mixes sodium with water and witnesses a violent reaction between the metal and water. this is best classified as

Tema [17]

A law is statement about an observed concept. A theory involves the explanation of scientific concepts or principles. A hypothesis is the predicted explanation about some concepts that has to be tested in order to prove it to be right. An observation is the observing the results of a scientific experiment carried out to test an hypothesis.

Here the given statement 'A chemist mixes sodium with water and witnesses a violent reaction between the metal and water,' can be classified as an observation as it explains what the chemists observes as a result of his chemical experiment or test..

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3 years ago

In the reaction K2CrO4 (aq) + PbCl2 (aq) 2KCl (aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction

pashok25 [27]

Reaction equation:
K₂CrO₄(aq) + PbCl₂(aq) → 2KCl(aq) + PbCrO₄(s)

Concentration = moles / Liter
moles(K₂CrO₄) = 3 x 0.025
= 0.075

By the equation, we see that the molar ratio of
K₂CrO₄ : PbCrO₄ is
1 : 1
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mass = moles x Mr
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2 years ago