A 0.500-g sample containing Na2CO3 plus inert matter is analyzed by adding 50.0 mL of 0.100 M HCl, a slight excess, boiling to r
1 answer:
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Answer:
See below
Step-by-step explanation:
(a) Shape
The formula for water is H-O-H.
The central O atom has four electron pairs around it. They try to get as far from each other as possible, so they point toward the corners of a tetrahedron.
Only two of the pairs have a hydrogen atom attached, so water has a bent shape. The H-O-H bond angle is about 104°.
(b) Chemical magnet
The O atom has a greater attraction than H for the shared electrons in the O-H bonds, so the electrons spend more time near the O.
This gives the O atom a partial negative charge (pink in the diagram) and the H atoms a partial positive charge (blue).
The water molecule acts like a chemical magnet because its negative end attracts the positive ends of other molecules, while its positive ends attract the negative ends of other molecules.
Answer: 0.1161 grams of mercury(II) sulfide) form.
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
a) Molarity of solution = 0.10 M
Volume of solution = 0.020 L
Putting values in equation 1, we get:
b) Molarity of solution = 0.010 M
Volume of solution = 0.050 L
Putting values in equation 1, we get:
According to stoichiometry :
1 mole of reacts with 1 mole of
Thus 0.0005 moles of reacts with=
moles of
Thus is the limiting reagent and
is the excess reagent.
According to stoichiometry :
1 mole of forms= 1 mole of
Thus 0.0005 moles of forms=
moles of
mass of
Thus 0.1161 grams of mercury(II) sulfide) form.