<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer:
3.10 i think i saw in quiz i hope you do a great job and ace the test
Step-by-step explanation:
So A lady walks into the bank I work at and she comes up to the counter and asks me to check her balance so I check her balance.........I push her over ;)
Answer:
tan A = -15/8.
Step-by-step explanation:
sin^2a = 1 - cos^2A
= 1 - (-8/17)^2
= 225/289
So sin A= 15/17
tan A = sin A / cos A
= 15/17 / -8/17
= 15/-8
= -15/8.
Answer:
Applying Quotient and power rule. Graphically, for x>0 both curves coincide.
Step-by-step explanation:
1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:
2) Check the graph below to see this equivalence. to see x>0 they both coincide.
