first you have to add the -4 to the -2 and you get 2. so 2x=2 then you divide 2 by 2x and get x=1
Turn both equations into slope-intercept form [ y = mx + b ].
x + 3y = 3
~Subtract x to both sides
3y = 3 - x
~Divide 3 to everything
y = 1 - x/3
~Reorder
y = -1/3x + 1
4x + 3y = -6
~Subtract 4x to both sides
3y = -6 - 4x
~Divide 3 to everything
y = -2 - 4x/3
~Reorder
y = -4/3x - 2
Graph of the equations will be shown below. Note that the solution of graphing two equations will be where both equations intersect. Both lines intersect at (-3, 2), hence making that the solution.
Best of Luck!
9514 1404 393
Answer:
a) x = -1, x = 4
b) y = x^2 -3x -4
Step-by-step explanation:
a) We observe the x-intercepts are x = -1 and x = 4. These are the solutions to y = 0, which is usually what we want in cases like this.
The solutions are x=-1 and x=4.
__
b) We know two of the factors are (x +1) and (x -4). There may be an additional constant factor for vertical scaling. One point we can check is the y-intercept.
y = a(x +1)(x -4)
For x=0, this is ...
y = a(1)(-4) = -4a
The y-intercept is y = -4, so we have a=1.
The factored equation is ...
y = (x +1)(x -4)
Multiplying this out gives the equation in standard form:
y = x^2 -3x -4
__
<em>Additional comment</em>
Your teacher may want the standard form equation to be ...
x^2 -3x -4 = 0
This is the equation of two specific points: x=-1 and x=4. It is not the equation of the graph.
