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2 years ago

How to write two different pairs of decimals whose sums are 14.1. One pair should involve regrouping

1 answer:

3 0

To solve, first let’s define regrouping:<span>
<span>=> Regrouping involves carrying and borrowing during subtraction and addition of the given numbers.

So let us have the non-regrouping decimal number:
=> 8.4
Next, the other regrouping decimal
=> 5.7

So now let us show how it becomes 14.1:
8.4
+5.7
14.1

Starting from the right, 4 + 7 is equal 11, so bring down 1 and carry 1. Now 8+5 = 13, but 13 + carry 1 = 14
<span>Thus, the answer is 14.1</span></span></span>

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Each day the gumball machine in the mall sells 919 gum balls. How many gum balls would it have sold after 160 day?

NikAS [45]

It would have sold 147,040 after 160 days

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3 years ago

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308.3 divided by 15 but estimate the divisor and divided

aev [14]

Answer:

308.13/15=20.553 or 21

Step-by-step explanation:

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plz mark brailiest

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2 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

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2 years ago

Tia is planning a sailing party for her friends. The boat rental is $150 plus an

mars1129 [50]

Answer:

16 people

Step-by-step explanation:

First subtract the cost of the rental from the amount of money:

$400-$150 = $250

Therefore Tia has $250 to spend for additional people. Then if each person is $15, divide the remaining amount of money by the amount of money per person:

$250/$15 = 16.67

Since you can't have 0.67 of a person she can have 16 people go with her.

This can also be modeled by this inequality:

$150 + 15x \leqslant 400$

4 0

3 years ago

The sides of a 30 60 90 triangle are 9 and 18.What is the third length of the triangle

Nimfa-mama [501]

Answer: 15.59 or 9√3

Step-by-step explanation:

We can use the Pythagorean Theorem to calculate the third side.

c² = a² + b² In a 30 60 90 Triangle, the hypotenuse is twice the length of the short leg of the right angle.

c is the hypotenuse. a is the short leg

18² = 9² + b²

324 = 81 + b² Subtract 81 from both sides.

324 - 81 = b² becomes b² = 243 Take the square root of both sides

b = 15.5884 . This can be rounded to 15.59 or 15.6 depending on significant digits or amount of precision required.

The proportions of the sides of the 30 60 90 triangle can also be used:

2² = 1² + b²

4 = 1 + b²

3 = b²

√3 = b

You can always multiply the length of the short leg by √3 to get the length of the side opposite the 60° angle

8 0

2 years ago