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NARA [144]
4 years ago
5

The density of gold is 19.3 the density of iron pyrite is 5.0 if a nugget of iron pyrite and a nugget of gold each have a mass o

f 50g what can u conclude about the volume of each nugget
Chemistry
1 answer:
exis [7]4 years ago
7 0
Density equals mas divided by volume. You know the density and mass so use it to solve for the volume.

d= m/v
d= 19.3 g/mL
m= 50g
v=?

Plug it in.    19.3= 50/v

To solve for v you do the opposite of 50 divided by v which is 50 time v.
That cancels v from the right side of the equation.  Do the same on the other side(times v)
19.3 * v=50

Now just divide both sides by 19.3 to get v alone.

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4 g of X2O3, an oxide of efement X, contains 2.8 g of X. How many moles of X<br> are there?
ziro4ka [17]

Moles of X are 0.925 moles.

A mole is a totally vital unit of dimension that chemists use.The mole, symbol mol, is the unit of amount of substance inside the worldwide device of gadgets. the amount quantity of the substance is a measure of how many simple entities of a given substance are in an item or sample. The mole is described as containing exactly 6.02214076×10²³ primary entities

mass  of X2O3 = 4 g

so moles = mass/molar mass

molar mass  of X2O3 =  2*X + 48 -

Given, that the mass of X = 2.8g

        mass of O = 4 - 2.8 = 1.2g

A mole of O = 1.2g/16 = 0.075 mole

∴ mole of X = 1 - 0.075 = 0.925 moles.

Learn more about moles here:-brainly.com/question/15356425

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4 0
2 years ago
Please help I’m timed !!!
Rashid [163]

Answer:

b. \% diss =4.4x10^{-2}\%

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

HClO\rightleftharpoons H^++ClO^-

We can write the equilibrium expression as shown below:

Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}

In such a way, via the definition of x as the reaction extent, we can write:

3.5x10^{-8}=\frac{x^2}{[HClO]}

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M

And finally the percent dissociation:

\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%

Which is choice b.

Best regards!

6 0
3 years ago
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Answer:It a Basic oxide

Plz trust Me

Explanation:

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