Answer:
weak bases
Explanation:
Leaving groups accept electron pairs. A strong base donates an electron pair while a weak base accepts an electron pair.
Since good leaving groups must readily accept electrons, weak bases are very good leaving groups.
The order of usefulness of halogens as leaving groups is: I > Br > Cl > F
Answer:
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Explanation:
Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.
A. One of the oxides (Oxide 1) contains 63.2% of Mn.
Mass of the oxide = 100g
Mass of Mn = 63.2 g
Mass of O = 100 - 63.2
= 36.8 g
Ratio of Mn to O = 63.2/36.8
= 1.72
Another oxide (Oxide 2) contains 77.5% Mn.
Mass of oxide = 100 g
Mass of Mn = 77.5 g
Mass of O = 100 - 77.5
= 22.5 g
Ratio of Mn to O = 77.5/22.5
= 3.44
Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.
B.
Oxide 1
Mass of Mn per 1 g of O = mass of Mn/mass of O
= 77.5/22.5
= 3.44 g/g of Oxygen.
Oxide 2
Mass of Mn per 1 g of O = mass of Mn/mass of O
= 77.5/22.5
= 3.44 g/g of Oxygen.
Answer:
endo takes energy in and exo releases it out
Explanation:
Answer:
The balanced reaction is given by,
⇒ 
Explanation:
The reaction is as given.
Lets count the number of each elements in the reaction.
<em>In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.</em>
<em>in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.</em>
<em>So we need to balance sodium and oxygen atoms in the reaction.</em>
<em>There is deficient of sodium and oxygen atoms on reactant side</em>.
Thus, multiply (NaNO3) by 2.
<em>Thus, sodium atoms become 2 , nitrogen 2 and oxygen 6. Total 7 oxygen atoms.</em>
Thus, the balanced reaction is,
⇒
