HURRY PLS HELP PLEASE: A 40.0-L sample of fluorine is heated from 363 Kelvin to 459 K. What volume will the sample occupy at the
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<span>The nitartion of methyl benzoate is expected to proceed as given in the equation below:
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In methyl benzoate there are 3 types of 1 H proton. The two ortho to the C=O group is a doublet at 8 ppm the 2 metal to the C=O is a multiple at 7.5 ppm and one para to the C=O is a multiplet at 7.5 ppm.
On nitration the ortho will probably show two signal one being a single with 3 proton integration and one a doublet with 1 H integration
The meta will show a highly down field singlet (coresponding to 1 proton), two unequal doublets (corresponding to 1 H each) and one multiplets (corresponding to 1H). This is the major product as seen from the 1H NMR.
The para isomer will come as two doublets which will be very close to each other there is a small signal for this set between 8.2 and 8.3 ppm.
Given :
Length , l = 59.8 m.
Breadth , b = 26.6 m.
Depth , d = 3.7 ft .
Density of water , .
To Find :
Mass of water in pool .
Solution :
First we will covert depth into m from ft .
For ,
So , volume of pool is :
We know , density is given by :
So ,
Putting given values in above equation :
Hence , this is the required solution.