Electrical<span> energy is produced by dry cell. Hope that helps.</span>
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Moles KClO₃ = 0.239
<h3>Further explanation</h3>
Given
Reaction
2KClO₃(s) ⇒2KCl(s) + 3O₂(g)
P water = 23.8 mmHg
P tot = 758 mmHg
V = 9.07 L
T = 25 + 273 = 298 K
Required
moles of KClO₃
Solution
P tot = P O₂ + P water
P O₂ = P tot - P water
P O₂ = 758 - 23.8
P O₂ = 734.2 mmHg = 0.966 atm
moles O₂ :
n = PV/RT
n = 0.966 x 9.07 / 0.082 x 298
n = 0.358
From equation, mol ratio KClO₃ : O₂ = 2 : 3, so mol KClO₃ :
= 2/3 x mol O₂
= 2/3 x 0.358
= 0.239
Answer:
6.707 × 10¹⁷
Explanation:
From the information given:
40 ^ K kütlesi = sütteki K kütlesi × 40 ^ K / 100 kütle yüzdesi
nerede;
sütteki K kütlesi = 1.65 mg of K/mL × 225 mL = 371.25 mg of K
∴
40 ^ K kütlesi = 371.25 × 0.012/100
40 ^ K kütlesi = 0,04455 mg = 4.455 × 10⁻⁵ grams
40 ^ K mol sayısı = 40 ^ K kütlesi / molar kütle
= 4.455 × 10⁻⁵/40
= 1.11375 × 10⁻⁶
Son olarak, 40 ^ K = mol × Avogadro sayısı atomları
= 1.11375 × 10⁻⁶ × 6.022 × 10^23
= 6.707 × 10¹⁷
