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2 years ago

11

Simple land plants lack seeds and

2 answers:

Marizza181 [45]2 years ago

8 0

Answer:

The answer is d: leaves.

Shalnov [3]2 years ago

8 0

Answer:

I think it's B. vascular tissue

Explanation:

That seems to be the answer

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I bet no one can solve this

Nikitich [7]

The answer is 89.4 g/mol cuz the two units carry positives so that means 8.50 flows for 2 more hours than usual.

3 0

3 years ago

The solubility of KNO3(s) in water increases as the..

makvit [3.9K]

The answer would be b. Temperature of the solution increases

Temperature determines the kinetic energy of the water molecule. Higher temperature will cause the molecule to moves faster and the compound (KNO3) could break solute molecule easier make it become more soluble. A higher pressure will increase the solubility of a gas, not solid

4 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

2 years ago

Can you please help me I need help<br><br> Thank you to the person that helped

Black_prince [1.1K]

Answer:

Model

Theory

Ellipse

Explanation:

Stan One Direction for better grade

7 0

2 years ago

Read 2 more answers

Classify each of the following as a physical or a chemical change. Give

hjlf

Answer:

a is a physical changes

b is physical changes

c is a Chemical change

d is a physical changes

5 0

2 years ago