How many grams of CO would be required to generate 635 g CO2
1 answer:
The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g
<h3>Stoichiometric problem</h3>First, let us get the equation of the reaction:
From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.
635 g of CO2 is to be generated.
Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles
Thus, the equivalent mole of CO required will also be 14.43 moles.
Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g
Hence, 404.14 g of CO will be required to produce 635 g of CO2
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Answer : The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -14.1 kJ/mol
R = gas constant = 8.314 J/K.mol
T = temperature =
Q = reaction quotient
= concentration inside the cell
= concentration outside the cell
Now put all the given values in the above formula, we get:
Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2