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Annette [7]
2 years ago
8

How many grams of CO would be required to generate 635 g CO2

Chemistry
1 answer:
vivado [14]2 years ago
7 0

The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g

<h3>Stoichiometric problem</h3>

First, let us get the equation of the reaction:

2CO + O_2 -- > 2CO_2

From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.

635 g of CO2 is to be generated.

Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles

Thus, the equivalent mole of CO required will also be 14.43 moles.

Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g

Hence, 404.14 g of CO will be required to produce 635 g of CO2

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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The empirical formula = molecular formula = C13H18O2

Explanation:

in 100% compound we have 75.6 % Carbon ( Molar mass = 12g/mole), 8.80% hydrogen ( Molar mass = 1.01 g/mole) and 15.5% Oxygen (Molar mass = 16.01 g/mole).

Carbon: 75.6g / 12 = 6.29

Hydrogen: 8.80/ 1 = 8.80

Oxygen: 15.5/ 16 = 0.97

⇒0.97 is the smallest so we divide everything through by 0.97

C: 6.29 / 0.97 =  6.48 ≈ 6.5

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To get rid of decimals, we multiply by 2  

C: 6.5 x 2 = 13

H: 9 x 2 = 18

O: 1 x 2 = 2

The empirical formula = C13H18O2

13x 12g/mol + 18x1g/mol  + 2x 16g/mol = 156 + 18 + 32 = 206g/mol  which is the molar mass of ibuprofen

The empirical formula = molecular formula = C13H18O2

6 0
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What is the definition of the molar mass of an element or compound?
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The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance(mol) .

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hope it may help you

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