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Annette [7]
1 year ago
8

How many grams of CO would be required to generate 635 g CO2

Chemistry
1 answer:
vivado [14]1 year ago
7 0

The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g

<h3>Stoichiometric problem</h3>

First, let us get the equation of the reaction:

2CO + O_2 -- > 2CO_2

From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.

635 g of CO2 is to be generated.

Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles

Thus, the equivalent mole of CO required will also be 14.43 moles.

Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g

Hence, 404.14 g of CO will be required to produce 635 g of CO2

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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Nitrous acid, hno2, has an acid dissociation constant - ka of 7. 1 ✕ 10-4. what are [h3o ], [no2-], and [oh -] in 0. 40 m hno2 - 4829 M [OH^-] = 1.439 x 10^-14 M

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