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e-lub [12.9K]
3 years ago
5

Trina and Seth walk 3 miles south and 5 miles east to get from their canoe to their tent. If a walkway existed between the canoe

and tent, how far would they then haveto walk? Round to the nearest mile. (PLEASE SHOW WORK!!)

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

6 miles

Step-by-step explanation:

The formula to find the hypotenuse of a right triangle is as follows,

\sqrt{a^{2} } +b^{2}

The line is supposed to be longer on the rooting but it won't go any longer so we just have to make do.

Anyways, a is 1 side length and b is the other. Doesn't matter which one you make b or a.

Now you just plug in and solve

\sqrt{9} +25 (that's after you square it)

add them

\sqrt{34}

simplify

5.83095189485

you can just stop at the hundredths place

5.83

You can estimate that it's about 6

and 6 is your answer

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What is the percent of 110 to 275
Ksenya-84 [330]
275 = 100%
110 = x%

Cross Multiply

275 * x = 100 * 110
275x = 11000
x = <u>11000</u>
        275
x = 40

110 = 40%

Solution: 40%
6 0
3 years ago
What are the excluded values of x for x^2-3x-28/x^2-2x-35
Tom [10]

Answer:

-5 and +7

Step-by-step explanation:

f(x) = (x²- 3x - 28)/(x² - 2x - 35)

The excluded values of x are those that make the denominator equal to zero.

x² - 2x – 35 =0

(x – 7)(x + 5) =0

x - 7 = 0

     x = 7

x+ 5 = 0

    x = -5

The excluded values of x are -5 and +7.

6 0
3 years ago
Read 2 more answers
A wedding planner uses 72 ivy stems for 18 centerpieces. When she arrives at the venue, she realizes she will only need 16 cente
adell [148]

Answer:

64 ivy stems

Step-by-step explanation:

Ratio of ivy stems to centerpieces:

72/18 = 4 ivy stems per centerpiece

Therefore,

16 x 4 = 64

7 0
2 years ago
Read 2 more answers
A right triangle has legs with the lengths of 2 and 5, find the length of the hypotenuse
Volgvan

Answer:

\sqrt{29}\ units

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the hypotenuse (the greater side)

a and b are the legs (perpendicular sides)

In this problem we have

a=2\ units\\b=5\ units

substitute

c^2=2^2+5^2

c^2=29

c=\sqrt{29}\ units

3 0
3 years ago
The top and bottom margins of a poster 6 cm each, and the side margins are 4 cm each. If the area of the printed material on the
Serga [27]

Answer:

p = 25,20 cm

h = 34,32 cm

A(min) = 864,86 cm²

Step-by-step explanation:

Let call p and h dimensions of a poster, ( length , and height respectively) and x and y  dimensions of the printed area of the poster then

p = x + 8        and      h = y + 12

Printed area = A(p) = 384 cm²     and   A(p) = x*y     ⇒ y = A(p)/x

y = 384 / x

Poster area  =  A(t) = ( x + 8 ) * ( y + 12 ) ⇒ A(t) =  ( x + 8 ) * [( 384/x ) + 12 ]

A(t)  =  384 + 12x + 3072/x + 96      A(t) = 480 + 3072/x + 12x

A(t)  =  [480x + 12x² + 3072 ] / x

A´(t) =  [(480 + 24x )* x  - (480x + 12x² + 3072]/x²

A´(t) =  0         [(480 + 24x )* x  - 480x - 12x² - 3072] =0

480x + 24x² -480x -12x² - 3072 = 0

12x² = 3072         x² = 296

x = 17,20 cm       and      y =  384/17,20      y = 22,32 cm

Notice  if you substitu the value of x = 17,20 in A(t) ; A(t) >0 so we have a minimun at that point

Then dimensions of the poster

p = 17,20 + 8  = 25,20 cm

h = 22.32 + 12 =34,32 cm

A(min) = 25,20 *34.32  

A(min) = 864,86 cm²

7 0
3 years ago
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