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Kazeer [188]
4 years ago
6

When solving this problem:

Mathematics
1 answer:
Lerok [7]4 years ago
3 0
The answer is 550 because you would be dividing
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Can you guys help me?
djyliett [7]

Answer:

Since the shirt costs $43.76, and you paid the cashier $50.76; the change you will get back will be $7.

Step-by-step explanation:

$43.76-$50.76 =$7

7 0
3 years ago
Read 2 more answers
Can someone help me solve this equation for 3/4w-1/2w-4= 12
muminat
Multiply both sides by 4
3w-2w-16=48
Combine like terms
w-16=48
Add 16 on both sides
w=64
3 0
4 years ago
Identify the property’s that justifies the statement: If 4x-3=7, then 4x=10
Alenkasestr [34]

Answer:

Step-by-step explanation:

The equation shown above does not show the substitution property. Instead, it shows the Addition Property of Equation where 3 is added to both of its sides. This is shown below,

                                   

                                   4x - 3 = 7

                               4x - 3 + 3 = 7 + 3

                                   4x = 10

4 0
4 years ago
There is a photo. No explanation needed just answer thank you
Iteru [2.4K]
It’s 125 because 5 over 3 is 5 (3) times so 5x5x5= 125 hoped this helped.
3 0
3 years ago
A fair die is rolled 10 times. Find the expected value of:a) the sum of the numbers in the ten rolls;b) the number of multiples
velikii [3]

Answer:

a) 3.5

b) 3.33

c) 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

Step-by-step explanation:

As given,

A fair die is rolled 10 times

a)

Expected value of Sum of the number in 10 rolls = \frac{1}{6}(1+2+3+4+5+6) = \frac{21}{6}

                                                                                = 3.5

∴ we get

Expected value of Sum of the number in 10 rolls = 3.5

b)

Ley Y : number of multiples of 3

Y be Binomial

Y - B(n = 10, p = \frac{2}{6} )

Now,

Expected value = E(Y) = np = 10×\frac{2}{6}  = 3.33

c)

Let m = total number of faces in a die

⇒m = 6

As die is roll 10 times

⇒n = 10

Now,

Let Y = number of different faces appears

Now,

Expected value, E(Y) = m - m\left(\begin{array}{ccc}m-1\\m\end{array}\right)^{n}

                                  = 6 - 6\left(\begin{array}{ccc}6-1\\6\end{array}\right)^{10} = 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

5 0
3 years ago
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