Answer: the length is 11 cm.
The width is 7 cm.
Step-by-step explanation:
Let L represent the length of the rectangular plastic box.
Let W represent the width of the rectangular plastic box.
The area of the rectangular top of the box is 77 square cm. This means that
LW = 77- - - - - - - ;- - - -1
The plastic box has a length 4 cm longer than its width. This means that
L = W + 4
Substituting L = W + 4 into equation 1, it becomes
(W + 4)W = 77
W² + 4W = 77
W² + 4W - 77 = 0
W² + 11W - 7W - 77 = 0
W(W + 11) - 7(W + 11) = 0
W - 7 = 0 or W + 11 = 0
W = 7 or W = - 11
Since the width cannot be negative, then W = 7cm
L = 77/7 = 11 cm
Answer:
≈ 3.6 x 10^1
Step-by-step explanation:
= (6.05 x 3.05) x 10^(5+4) / (4.27 x 1.2) x 10^(4+4)
= 18.4525 x 10^9 / 5.124 x 10^8
= (18.4525 / 5.124) x 10^(9-8)
≈ 3.6 x 10^1
0.15c>10+0.10c
0.05c>10
c>200
Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is
Slope of lines NY is
Product of slopes of two perpendicular lines is -1. So,
The perpendicular bisector of NY passes through (-4,1) with slope 
. So, the equation of perpendicular bisector of NY is
Add 1 on both sides.
Therefore, the equation of perpendicular bisector of NY is .
Line them up
3x3= 9, 3x2= 6, 3x5= 15
Add a 0 under the 9, 7x3= 21, leave the 1 and carry the 2, 7x2= 14+2= 16 leave the 6 and carry the 1, 7x5= 35+1= 36
9+0= 9, 6+1= 7, 5+6= 11 leave 1 carry 1, 1+6= 7+1= 8, 0+3= 3
523
x 73
———
1,569
+ 36,610
———
38,179
