Can someone help me with 7?
1 answer:
Solving the equation for y puts it in slope-intercept form.
This tells you one point can be plotted on the y-axis at y=-1. Another point can be plotted 3 units up and 5 units to the right of that one, at (5, 2). The graph is the line through those points.
Since you're asked to plot at least 3 points, your third point could be 5 units left and 3 units down from the first one, at (-5, -4).
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The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
