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galben [10]
3 years ago
6

What is the axis of symmetry for f(x) = 2x2 − 4x + 5? (1 point) x = −2 x = −1 x = 1 x = 2

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

x = 1

Step-by-step explanation:

To find the axis of symmetry use the formula: x = -b/2a. In the quadratic equation of 2x^2 - 4x + 5:

  • a = 2
  • b = -4
  • c = 5

Substitute a and b into the formula.

x = -(-4)/2(2)

This simplifies to 4/4, which is then simplified to 1.

Therefore the axis of symmetry is x = 1.

Gnom [1K]3 years ago
4 0

Answer:

y = 2x^2 − 4x + 5

y = 2(x^2 − 2x) + 5

y = 2(x^2 − 2x + 1 - 1) + 5

y = 2(x^2 − 2x + 1) + 5 - 2

y = 2(x - 1)^2 + 3

x = 1 is the axis of symmetry.

Do you agree?



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From the properties of conditional statement we know that:

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1 year ago
Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn
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Answer:

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Step-by-step explanation:

For this case we need to proof that: Let X_1, X_2, ...X_n \in R be independent random variables with a common CDF F_0. Let F_n be their ECDF and let F any CDF. If F \neq F_n then L(F)

Proof

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We can define p_j = F(z_j) +F(z_j-) and assuming the probability \hat p_j = \frac{n_j}{n}.

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log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})

log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)

So then we have that:

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And with that we complete the proof.

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