If you expand the square, you have

Simplify the right hand side:

Cancel the -3x appearing on both sides:

Multiply both sides by 4:

Consider the square root of both terms (using the doubles sign):

Answer:
x = 28 cm
Step-by-step explanation:
Given:
Area of link shaded regions = 84 cm²
Required:
The value of x (diameter of the semicircle/length of the rectangle)
Solution:
Diameter of the semicircle = 2r = x
Length of rectangle (L) = 2r = x
Radius of semicircle (r) = ½x
Width of rectangle (W) = radius of semicircle = ½x
Use 3.14 as π
Area of the link shaded regions = area of rectangle - area of semicircle
Thus:
Area of the link shaded regions = (L*W) - (½*πr²)
Plug in the values
84 = (x*½x) - (½*3.14*(½x)²)
84 = x²/2 - (1.57*x²/4)
84 = x²(½ - 1.57/4)
84 = x²(0.5 - 0.3925)
84 = x²(0.1075)
Divide both sides by 0.1075
84/0.1075 = x²
781.4 = x²
√781.4 = x
27.9535329 = x
x = 28 cm
Answer: 15 cases
Step-by-step explanation:
1 gallon = 4 quarts
Hence from 30 gallon oil drum, 30 x 4 = 120 quart-size bottles can be filled.
One case will pack 8 quart size bottles.
Hence number of cases = 120/8 = 15 cases
Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
Answer:
y = -
x -2
Step-by-step explanation:
The line is going down to the right so it has the negative slope, with a y- intercept of (0, -2) and a slope of m = rise/run = -5/3