Since CB || ED and CB = ED,
by the alternate interior angles theorem,
mE = mC, and mD = mB.
with CB = ED, we can conclude that CBF = EDF, by SAS congruent theorem.
Answer:
6 titles and 16 acts were elaborated
Step-by-step explanation:
Let the number of titles be t and the number of acts be a
Since the total is 22 operations:
a + t = 22 •••••••(i)
Total amount from titles = 3500 * t = 3500t
Total amount from acts = 2000 * a = 2000a
2000a + 3500t = 53,000 ••••••(ii)
From i, a = 22-t
Insert this in ii
2000(22-t) + 3500t = 53,000
44,000 - 2000t + 3500t = 53,000
1,500t = 53000-44000
1500t = 9000
t = 9000/1500
t = 6
But a = 22 -
= 22-6 = 16
Answer:
i wanna say -80?
Step-by-step explanation: so when you go from -8 to -11 its counts by 3 -11 to -14 its 3 so count up to get our answer. i just seen how many was in each 5 set which was 12 so i did -20 -12 so then i just added up and got -80
Answer:
$90
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 9%/100 = 0.09 per year,
then, solving our equation
I = 2000 × 0.09 × 0.5 = 90
I = $ 90.00
The simple interest accumulated
on a principal of $ 2,000.00
at a rate of 9% per year
for 0.5 years is $ 90.00.
60 children tickets and 190 adult tickets were sold.
<u>Step-by-step explanation:</u>
Let the no. of adult tickets sold be 'a'
Let the no. of children tickets sold be 'c'
Total tickets sold = 250
Cost of 1 children ticket = $2.5
Cost of 1 adult ticket = $4
Total money collected= $910
Given that,
a + c = 250
a = 250 - c
4a + 2.5c = 910
Substitute a value
4(250 - c) + 2.5c = 910
1000 - 4c + 2.5c = 910
1000 - 1.5c = 910
-1. 5c = -90
1.5c = 90
c = 90/1.5
c = 60
a + c = 250
a + 60 = 250
a = 190
60 children tickets and 190 adult tickets were sold.
