3 years ago

I really need help on this!

Mathematics

2 answers:

solong [7]3 years ago

8 0

Answer:

1,067.23

Step-by-step explanation:

1456.23 subtracted by 389 = 1,067.23

Setler [38]3 years ago

6 0

Answer:

1067.23

Step-by-step explanation:

1456.23

-398

______

1067.23

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Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

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The formula subject to q is $\frac{4+3p}{5}$

Explanation:

The given formula is $5(q+p)=4+8 p$

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The formula subject to q can be determined by solving the formula for q.

Let us solve the formula.

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Subtracting both sides by 5p, we have;

$5q=4+3p$

Dividing both sides by 5, we get;

$q=\frac{4+3p}{5}$

Thus, the formula subject to q is $\frac{4+3p}{5}$

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