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brilliants [131]
3 years ago
15

Show (2.3)(5.06) as a fraction multiplication problem

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0
2.3 would be 2+(3/10), which we would then use a common denominator of 10 to get 20/10+3/10=23/10. 5.06 would be 5+(6/100). 6/100 can be reduced by a factor of 2 to 3/50, which we would then use a common denominator of 50 to get 250/50+3/50=253/50. As a fraction multiplication problem, this would look as (23/10)(253/50)
Tcecarenko [31]3 years ago
5 0
Your answer is (23/10)(253/50)
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Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p
Aleks [24]

Answer:

11000 JY.

Step-by-step explanation:

According to today's exchange rate

1 US dollar = 110 JY

100 US dollars = 100 * 110 JY

You should get 11000 JY.

Pick the answer that is closest to this exchange rate.

8 0
2 years ago
Need help with my math simplify
nlexa [21]

2+42/-2-5(-3)  Multiply -5 and -3.

2+42/-2+15 Now, add the non fraction numbers. (2 and 15)

17+42/-2 Here, you want to reduce the fraction if you can, and yes, you can. Find the divisible number that is the lowest one that both can be evenly divided by. For this problem, it’s -2.

17-21. And from here, its easy. Just a simple subtraction problem.

-4 should be the correct answer.

3 0
3 years ago
6% of a value is 510
Dennis_Churaev [7]

Answer:

The value is 8500

Step-by-step explanation:

Of means multiply and is means equals

6% * V = 510

Change percent to decimal form

.06V = 510

Divide each side by .06

V = 510/.06

V =8500

6 0
3 years ago
Read 2 more answers
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
The table shows the number of miles each person ran this week who ran more miles by te end of the week How many More?
Tasya [4]
To calculate who ran more, you add up the total miles
Pat = 2.75+3+2.5 = 8.25
Toby = 2+2.25+3.5 = 7.75
Now subtract to see who ran more
Pat ran 0.5 miles more than Toby.

Hope this helps 
5 0
2 years ago
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