Answer:
4
Step-by-step explanation:
Given :
5c+cd where, 
and d=15
Now,
5×
=1+3
=4
Answer is 4
Heres the work g..........
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Let x,y,z be those numbers.
x+y+z = 12
Since x,y,z are consecutive: y=x+1, and z = x+2
Let's replace y and z by their new values:
x+x+1+x+2=12
3x+3=12
You subtract 3 from each side to get variables on a side, and numbers on the other:
3x=9
You divide both sides by 3:
x=3
y=x+1 = 3+1 = 4
z=x+2 = 3+2 = 5
So the numbers are 3; 4 and 5.
You can re-check your answers (very important):
3+4+5 = 12
3;4;5 are consecutive numbers.
The answer has been approved.
Hope this Helps! :)
Answer:
21
Step-by-step explanation:
