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3 years ago

Need help ASAP!!! Pleaseee

Mathematics

1 answer:

stira [4]3 years ago

6 0

Step one, factor the denominators:
5x/(x-1)(x-6)-3(x+2)/(x+2)(x-6)
step two: make the denominators the same, the first fraction multiple (x+2), both top and bottom, the second one multiply (x-1), both top and bottom
simplify, I eventually get the answer (2x+3)/(x^2-7x+6)

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Abigail realizes that she has too much debt. What is a financially irresponsible decision for Abigail?

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8 0

3 years ago

Evaluate the expression if y=4.4 and z= 12 z2+ 8y

Evgen [1.6K]

Answer: 59.2

Step-by-step explanation:

Take your equation

z2+8y

Now plug in the values given

(12)2+8(4.4)

24+35.2

59.2

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3 years ago

Suzy can bike 40 miles in 30 minutes. How far can she go in 2 hours?

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2 years ago

Read 2 more answers

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

So, the 95% confidence interval is (46.4, 53.6)

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

So, the 95% confidence interval is (47.9, 52.1)

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

Notice that the margin of error decreases when the sample size increases.

4 0

3 years ago

He solution is n = –2 verified as a solution to the equation 1.4n + 2 = 2n + 3.2. What is the last line of the justification?

Nimfa-mama [501]

Answer:

$-0.8=-0.8$

Step-by-step explanation:

We have been given that n=-2 verified as a solution to the equation $1.4n+2=2n+3.2$ .

As n=-2 is the solution for our given equation, so it will satisfy our equation.

Let us substitute n=-2 is our given equation.

$1.4*-2+2=2*-2+3.2$

$-2.8+2=-4+3.2$

$-0.8=-0.8$

Since the value of n satisfies our equation, therefore, last line of the justification will be $-0.8=-0.8$ .

5 0

2 years ago