I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².
Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.
Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.
Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.
Add each length up and you get a perimeter of roughly 11.4
Answer:
2 units
Step-by-step explanation:
Vpyramid = ⅓ x base area x height
70 = ⅓ x base area x 6
70 = 2 x base area
base area = 70/2 = 35 units
Vprism = base area x height
70 = 35 x height
height = 70/35 = 2 Units
Answer:
y - 8 = x + 7
Step-by-step explanation:
To write the equation of a line use the point slope form. Substitute m = 1 and (-7,8).

Answer:
1) How does "Abe" relate to the merry-go-round? (The problem doesn't seem to say.)
2) How many people did each person provide for? So how many dozens were brought? How many are in a dozen? So how many cookies were brought?
Step-by-step explanation:
nm the top
There are n seats on a merry- go-round. A boy takes n rides. Between each ride, he moves clockwise a certain number of places to a new horse. Each time he moves a different number of places. Find all n for which the boy ends up riding each horse.
2) So if there are n horses, first the boy could move by one place then he could move by n+1 places then by 2n+1 so on and so forth, until he moves (n−2)n+1 places, in which case he'd would have been ridden each horse only one time and taken unique number of steps, which implies that all n's satisfy given condition.
1) I don't know how to cancer this let me resheerch and ill get back to you
P>S let this be help only if you need to annotate or reword thx