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2 years ago

In which type of quadrilateral are consecutive sides congruent?

Mathematics

2 answers:

Kipish [7]2 years ago

3 0

Square, I would believe.

Naddika [18.5K]2 years ago

3 0

Verifying the previous answer of Square.
Congruent means Equal, Consecutive sides means the sides that are touching. a square's sides are all equal by definition of a square, which includes its consecutive sides, meaning a squares consecutive sides are, in fact, congruent.
I know you already got an answer I just wanted to help make sure you understand why that is, hope this helps.

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Cerrena [4.2K]

Answer:

$500

Step-by-step explanation:

$25 = 5% of x

0.05x = 25

x = 25/0.05

x = 500

Answer: $500

4 0

2 years ago

The grill was regularly priced at $58, but Jared had a coupon for 25% off. How much money did Jared save by using his coupon?

frosja888 [35]

Answer:

He saves $14.50

Step-by-step explanation:

We can find the discount by multiplying the price by the percentage off

58* .25 = 14.50

He saves $14.50

7 0

2 years ago

Read 2 more answers

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

2 years ago

Read 2 more answers

NEED HELP ASAP!!!

Sergeeva-Olga [200]

Answer:

(b) $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

Step-by-step explanation:

Let E: Event of getting a 3 in the spinner.

So, the number of favorable outcomes = 11

Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}

= {13 +10 +11+16+11} = { 61}

So, the total number of outcomes = 61

$\textrm{Probability of Event E} = \frac{\textrm{Number of favorable events}}{\textrm{Total number of outcomes}}$

So, here $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

3 0

2 years ago

What's the ratio of 75 to 80?

oksano4ka [1.4K]

Answer:

75:80 OR 15:16

Step-by-step explanation:

7 0

3 years ago