Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
17b
Step-by-step explanation:
8980
80987
78987=
A median is the middle number of a data set.
To find it put the numbers in order.
78, 69, 69, 96, 99
Then find the middle number
78, 69, *69,* 96, 99
The median is 69
A mode is the number that appears the most in a set of numbers.
78, *69, 69,* 96, 99
The mode is 69
To find the mean or average of a set of numbers, add all the numbers together then divide by the number of numbers there are.
99+69+96+69+78 = 411
411/5 = 82.2
The mean is 82.2
Hope this helped! If you have anymore questions or don't understand, please comment on my profile or DM me. :)
The answer is (rounded to the nearest tenth) about 5.7 and since neither 18 or 2 have a perfect square, so this is irrational.
I believe you're answer is false.
