You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)
(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)
Answer:
24 for being able to not have one, 6 for having one of each
Step-by-step explanation:
multiplication
with the option of none
4*2*3=24
without the option of none
3*1*2=6
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
Answer:
The second choices is the answer
{(-6,6), (8, 2), (8, -1), (3,3)} as you can see there's a repeating value of x or the Domain which is the 8.
Answer:2.91666666667
Step-by-step explanation:
